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Question

Find the $$15^{th}$$ term of the G.P. 3, 12, 48, 192, ..........


A
3×415
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B
3×414
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C
3×416
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D
315
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Solution

The correct option is B $$3\,\times\,4^{14}$$
Clearly, the given GP has first term $$a=3$$ and common ratio $$r=4$$.
$$\therefore\space a_{15}=ar^{14}$$
$$=>a_{15}=3\times(4)^{14}$$

Mathematics

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