Question

# Find the $$15^{th}$$ term of the G.P. 3, 12, 48, 192, ..........

A
3×415
B
3×414
C
3×416
D
315

Solution

## The correct option is B $$3\,\times\,4^{14}$$Clearly, the given GP has first term $$a=3$$ and common ratio $$r=4$$.$$\therefore\space a_{15}=ar^{14}$$$$=>a_{15}=3\times(4)^{14}$$Mathematics

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