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Question

Find the 4th term from the end in the expansion of (4x552x)9


Solution

TN=Tr+1=(1)rnC2xnryr

4th term from the end 7th term from beginning 

N=7,R=6,n=9,x=4x5,y=52x

T7=T6+1=(1)69C6(4x5)3(52x)6

=9×8×73×2×r3×5653×26×x3x6

=9×8×7×536×x3=9×8×7×1256×x3

=10500x3


Mathematics
RD Sharma
Standard XI

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