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Question

Find the 60th term of the AP 8, 10, 12, ., if it has a total of 60 terms and hence find the sum of its last 10 terms.

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Solution

A.P is 8,10,12......................
Then first term is 8 and common difference is 2.
an=a+(n1)d.
Then a60=8+(601)2=8+59×2=126
Last 10 term =a51,a52..................a60
Then a51=8+(511)2=108
So total of last 10 terms=102[108×2+(101)2]=216+81=234×5=1170

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