Question

# Find the absolute sum of roots of the equation $$\displaystyle x^{2}+3x-4=0$$

Solution

## $$\displaystyle x^{2}+3x-4=0\Rightarrow x^{2}-x+4x-4=0$$$$\displaystyle \Rightarrow x\left ( x-1 \right )+4\left ( x-1 \right )=0\Rightarrow \left ( x+4 \right )\left ( x-1 \right )=0$$$$\displaystyle \therefore x=-4$$ or x = 1Absolute Sum of roots$$|-4+1| = 3$$Mathematics

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