Here,
→F=3^i+4^j−5^k
d=5^i+4^j+3^k
→F.d=15+16−15=16
|F|=√50
|d|=√50
cosθ=F.d|F||d|
θ=cos−(1650)
θ=cos−(0.32)
→Fond=→Fcosθ
=√5016√50
=16
The angle between the two vectors →A=3^i+4^j+5^k and →B=3^i+4^j−5^k will be