Question

# Find the angle of projection of a projectile for which the horizontal range and maximum height are equal.

Solution

## $$R=\frac { { u }^{ 2 }sin2\theta }{ g } =H=\frac { { u }^{ 2 }{ sin }^{ 2 }\theta }{ 2g } \\ \Rightarrow 2sin\theta cos\theta =\frac { { sin }^{ 2 }\theta }{ 2 } \\ \Rightarrow tan\theta =4\Rightarrow \theta ={ tan }^{ -1 }(4)$$Physics

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