Question

Find the angle which is equal to its complement.(in ${}^{\circ }$)

Answer 1

Let the measure of the required angle be $x^o$.

Since, the angle is equal to its own complement, both the angle and its complement will be equal.

Then,

$⟹x^o+x^o={90}^o$

$⟹2x={90}^o$

$⟹x={\frac{90}{2}}^o$

$⟹x={45}^o$.

Hence, the required angle measures ${45}^o$.