Question

Find the angular fringe width in Young's double slits experiments with a blue-green light of wavelength 6000A. The separation between the slits is $3.0\times {10}^{-3}m$.

Answer 1

In Young's double slits experiment angular fringe width is given by

$\theta =\frac{\lambda }{d}$ where, $\lambda$ is wavelength of blue-green light and $d$ is separation between slits.

Here,

$\lambda =6000\dot{A}=6000\times {10}^{-10}m$

$d=3\times {10}^{-3}m$

$so,\theta =\frac{6000\times {10}^{-10}}{3\times {10}^{-3}}$

$\theta =2\times {10}^{-4}$

$\theta ={0.0002}^0$