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Question

Find the approximate value of mode for the following data:


Marks
5060
6070
7080
8090
90100
Students
12
10
24
5
9


A
71
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B
72
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C
73
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D
74
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Solution

The correct option is D 74

Here the frequency of class interval 7080 is the maximum.

So, it is the modal class

Now

l = lower limit of modal class =70

f1= frequency of modal class =24

f0= frequency of class preceding the modal class =10

f2= frequency of class succeeding the modal class =5

h=class interval width =10


Mode =l+(f1f02f1f0f2)×h

=70+(24102×24105)×10

=70+(144815)×10

=70+4.24

=74.24

Mode 74


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