CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the area of a figure formed by joining the midpoints of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm.

Open in App
Solution


Let ABCD be a rhombus and P, Q, R and S be the midpoints of AB, BC, CD and DA, respectively.
Join the diagonals, AC and BD.
In ∆ ABC, we have:
PQ ∣∣ AC and PQ = 12AC [By midpoint theorem]
PQ=12×16=8 cm

Again, in ∆DAC, the points S and R are the midpoints of AD and DC, respectively.
SR ∣∣ AC and SR = 12AC [By midpoint theorem]
SR=12×12=6 cm
Area of PQRS=length×breadth=6×8=48 cm2

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Figures on same base and between same parallels
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon