Find the area of a rhombus one side of which measures 20 cm and one of whose diagonals is 24 cm.
Let ABCD is a rhombus with the diagonals AC and BD which intersect each other at O.
Given AC = 24cm.
Then AO = 12cm.
Let BO = x and AB = 20cm.
By Pythagoras theorem, we know that
x = 16cm.
Diagonal BD = 2 * 16
We know that Area of the rhombus = 1/2 * (product of diagonals)
= 1/2 * 24 * 32
= 12 * 32
= 384 sq.cm.