Find the area of a sector of a circle with radius $6 c m$ if angle of the sector is $60^{\circ} .$

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Solution

Area of a sector is given as
$= \frac{θ}{360} \times π \times r^{2}$

$= \frac{60}{360} \times \frac{22}{7} \times 6 \times 6$

$= \frac{132}{7} c m^{2}$

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