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Question

Find the area of a triangle whose two sides are 18 cm and 10 cm and the perimeter is 42 cm.

A
83.67 cm2
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B
46.12 cm 2
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C
77.15 cm2
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D
69.69 cm2
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Solution

The correct option is

D

69.69 cm2



Let a, b and c be the sides of triangle.
Perimeter =a+b+c=42 \text{ cm}$
a=18, b=10
As a+b+c=42
c=42ba=421810
c=14
Area of triangle =s(sa)(sb)(sc)
where, s=a+b+c2=18+10+142=422=21 cm
Area of triangle =21(2118)(2110)(2114)

=21(3)(11)(7)

=21(3×7)(11)

=21×21×11

=2111

=21×3.3166

=69.64

Area of triangle =69.69 cm2


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