Find the area of an equilateral triangle each of whose side is 4 cm long?

2 \sqrt{3}

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3 \sqrt{3}

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5 \sqrt{3}

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4 \sqrt{3}

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Solution

The correct option is D $4 \sqrt{3}$
solution:
$A r e a = \frac{\sqrt{3}}{4} r^{2}$
$A r e a = \frac{\sqrt{3}}{4} 4^{2}$
$A r e a = \frac{\sqrt{3}}{1} 4$
hence the correct opt: D

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