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Question

# Find the area of ΔPCD, P lies on the line AB, where O is the centre of the outer circle with radius 6.5 cm. ABCD is a rectangle, one of its sides is 5 cm.

A
30 cm2
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B
45 cm2
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C
36 cm2
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D
50 cm2
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Solution

## The correct option is A 30 cm2If radius = 6.5 cm, then BD = 13 cm. By Pythagoras theorem, The other side of the rectangle has to be 12 (Since 5, 12 and 13 from a Pythagoras triplet) So, area (ΔPCD)=(12)×12×5=30 It does not matter which side is 12 or 5. Area remains the same.

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