Question

# Find the area of given figure, if AB = EF = 12 cm, CD = 10 cm and PQ = QR = 5 cm.

A
55 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
60 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
110 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
220 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 110 cm2PQ is perpendicular to AB and CD. ⇒ AB || CD ⇒ ABCD is a trapezium Similarly, QR is perpendicular to CD and EF. ⇒ CD || EF ⇒ CDEF is a trapezium Therefore, Area of given figure = Area of trapezium ABDC + Area of trapezium CDFE We know that Area of trapezium =12×(Sum of parallel sides)×height Area of trapezium ABDC =12×(AB+CD)×PQ =12×(12+10)×5=12×22×5 = 11×5 = 55 cm2 Area of trapezium CDFE =12×(EF+CD)×QR =12×(12+10)×5=12×22×5 = 11×5 = 55 cm2 Therefore, Area of given figure = 55 + 55 = 110 cm2

Suggest Corrections
0
Related Videos
Area of Trapezium
MATHEMATICS
Watch in App
Explore more