Question

Find the area of the figure given below.

• A. h sq.units
• B. h(a+b)sq. units
• C. 2h(a+b) sq.units
• D. Can't be determined

Answer 1

The correct option is A

h sq.units

Area of trapezium = Area of rectangle + Area of the two triangles
$=base\times height+2\times \frac{1}{2}\times base\times height$
$=a\times h+2\times \frac{1}{2}\times h\times \left(\frac{b-a}{2}\right)$
$=a\times h+\frac{h(b-a)}{2}$
$=h[a+\frac{b-a}{2}]$
$=h\left[\frac{b+a}{2}\right]$
Area of trapezium $=h\frac{(a+b)}{2}$sq.units