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Question

Find the area of the parallelogram whose adjacent side are a=3^i+4^j+3^k, b=3^i2^j+^k.

A
23 sq. units.
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B
53 sq. units.
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C
63 sq. units.
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D
83 sq. units.
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Solution

The correct option is D 83 sq. units.
Area of parallelogram =|(a×b)|

But a×b=∣ ∣ ∣^i^j^k123321∣ ∣ ∣=8(i+j+k)
|a×b|
=81+1+1
=83 sq. units.

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