Question

Find the area of the quadrilateral ABCD in which AD = 24 cm, ∠ BAD = 90o and Δ BCD is an equilateral triangle having each side equal to 26 cm. Also, find the perimeter of the quadrilateral. [Given, √3 = 1.73.]

Solution

ΔBDC is an equilateral triangle with side a = 26 cm

Area of ΔBDC =√3a24=√3×2624=√3×6764=292.37 cm2

By using Pythagoras theorem in the right-angled triangle ΔDAB, we get:

AD2+AB2=BD2242+AB2=262AB2=262−242=676−5762=100AB=10 cm

Area of ΔABD =12×base×height12×10×24=120 cm2

Area of the quadrilateral = Area of ΔBDC + Area of ΔABD

=292.37+120=412.37 cm2

Perimeter of the quadrilateral =AB+AC+CD+AD=24+10+26+26=86 cm

Suggest corrections

0 Upvotes

Similar questions

View More...

Same exercise questions

View More...

People also searched for

View More...

- About Us
- Contact Us
- Investors
- Careers
- BYJU'S in Media
- Students Stories - The Learning Tree
- Faces of BYJU'S – Life at BYJU'S
- Social Initiative - Education for All
- BYJU'S APP
- FAQ
- Support

© 2021, BYJU'S. All rights reserved.