Find the area of the sector of a circle having radius 6 cm and of angle $30^{\circ}$ . [Take $π$ = 3.14 ]

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Solution

Area of the sector = $π r^{2}$ $\times$ $\frac{θ}{360^{o}}$
=3.14 $\times$ 6 $\times$ 6 $\times$ $\frac{30^{o}}{360^{o}}$
=18.84 $c m^{2}$

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