Find the area of trapezium-in cm-2- 45484940-

Byju's Answer

Standard IX

Mathematics

Theorem 2: Perpendicular from the Center to a Chord Bisects the Chord

Find the area...

Question

Find the area of trapezium (in ${c m}^{2}$ ).

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Solution

The correct option is C 49
Area of trapezium

= $\frac{1}{2}$ (perpendicular distance between two parallel sides)(sum of the length of the parallel sides)

= $\frac{1}{2}$ (7)(8+6)

= 49 ${c m}^{2}$

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(i) Area of triangle = $\frac{1}{2} \times (. . . . . . . . .) \times (. . . . . . . . .)$ .
(ii) Area of a ||gm = $\frac{1}{2} \times (. . . . . . . . .) \times (. . . . . . . . .)$ .
(iii) Area of a trapezium = $\frac{1}{2} \times (. . . . . . . . .) \times (. . . . . . . . .)$ .
(iv) The parallel sides of a trapezium are 14 cm and 18 cm and the distance between them is 8 cm. The area of the trapezium is ......... cm².