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Question

Find the centroid of the triangle whose vertices are $$(2,4),(6,4),(2,0)$$.


A
(73,4)
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B
(103,83)
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C
(10,8)
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D
None of these
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Solution

The correct option is C $$\left(\dfrac{10}{3}, \dfrac{8}{3}\right)$$
The centroid of a triangle ABC is given by:

$$C=\left(\dfrac{x_1+x_2+x_3}{3},\dfrac{y_1+y_2+y_3}{3}\right)$$

$$x_1,x_2,x_3$$ are the x-coordinate’s of the vertices of the triangle.

$$y_1,y_2,y_3$$ are the y-coordinate’s of the vertices of the triangle.

$$=\left(\dfrac{2+6+2}{3}, \dfrac{4+4+0}{3}\right)$$

$$=\left(\dfrac{10}{3}, \dfrac{8}{3}\right)$$

Maths

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