Question

Find the centroid of triangle whose vertices are $(5,3),(9,4)$ and $(3,-7)$.

• A. $0,\frac{17}{3}$
• B. $17,3$
• C. $\frac{17}{3},0$
• D. None of the above

Answer 1

The correct option is C $\frac{17}{3},0$

The centroid of triangle is given by

$\Rightarrow x=\frac{x_1+x_2+x_3}{3}$ and $y=\frac{y_1+y_2+y_3}{3}$

$\Rightarrow x=\frac{5+9+3}{3}$ and $y=\frac{3+4-7}{3}$

$\Rightarrow x=\frac{17}{3}$ and $y=0$

$\therefore$ Centroid $\equiv (\frac{17}{3},0)$