CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Find the charge of $$48 g$$ of $${ Mg }^{ 2+ }$$ ions in coulombs.


A
2.4×1023C
loader
B
6.82×105C
loader
C
3.86×105C
loader
D
1.93×105C
loader

Solution

The correct option is C $$3.86\times { 10 }^{ 5 }C$$
Molar mass of $${Mg}^{+2} = 24 g$$
Given mass of $${Mg}^{+2} = 48 g$$
No. of moles of $${Mg}^{+2} = \cfrac{\text{Given mass}}{\text{Molar mass}} = \cfrac{48}{24} = 2 \text{ moles}$$
1 mole of $${Mg}^{+2}$$ = 2 moles of electrons
$$\therefore$$2 moles of $${Mg}^{+2}$$ = 4 moles of electrons
$$\therefore$$ No. of electrons = no. of moles of electrons $$\times$$ Avogadro's constant
$$\Rightarrow$$ No. of electrons $$= 4 \times 6.023 \times {10}^{23} = 2.4 \times {10}^{24}$$
As we know that,
Charge on 1 electron $$= 1.6 \times {10}^{-19} C$$
$$\therefore$$ Total charge on 48 g $${Mg}^{+2} = \text{no. of }{e}^{-}s \times \text{charge on 1 } {e}^{-} = \left( 2.4 \times {10}^{24} \right) \times \left( 1.6 \times {10}^{-19} \right) = 3.84 \times {10}^{5} C \approx 3.86 \times {10}^{5} C$$
Hence, the correct answer is $$3.86 \times {10}^{5} C$$.

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image