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Question

Find the closest distance of approach.

A
1.4A0
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B
2.8A0
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C
2.8pm
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D
2.8fm
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Solution

The correct option is C 2.8A0
the kinetic energy of particle is converted into interaction(repulsive) energy
K.E.initial+P.Einitial=P.Efinal

12mv2+F.xi=F.xf

12×(1.67×1027)×(3×105)2+2.12×102652×5=2.12×1026x2×x

by solving this we get

x=2.12×2×1091.67×9=2.8×1010=2.8˙A

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