Find the common difference of AP whose nth term in 6n+2.

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Solution

$a n = 6 n + 2$

$a_{1} = 6 \times 1 + 2 = 8$

$a_{2} = 6 \times 2 + 2 = 14$

$a_{3} = 6 \times 3 + 3 = 20$

$d = a_{2} - a_{1} = 14 - 8 = 6$

$c o m m o n d i f f e r e n c e = 6.$

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