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Question

# Find the coordinates of the intersection of the lines 2x−3y+1=0 and 2x+4y+5=0.

A

(1914, 47)

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B

(1914, 47)

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C

(1914, 47)

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D

(1914, 47)

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Solution

## The correct option is D (−1914, −47) 2x−3y+1=0 - - - - - (1) 2x+4y+5=0 - - - - - (2) Equation (1) can be written as 2x−3y=−1 - - - - - (3) Equation (2) can be written as 2x+4y=−5 - - - - - (4) (3) - (4) ⟹ −7y=4 ⟹ y=−47 Substituting y=−47 in equation (3), 2x−3(−47)=−1 ⟹2x+127=−1 ⟹2x=−1−127 ⟹x=−1914 ∴ The coordinates of the intersection of the lines 2x−3y+1=0 and 2x+4y+5=0 are (−1914, −47).

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