Find the cube of :
$2 a - 1$

Open in App

Solution

$(2 a - 1)^{3} = (2 a)^{3} - (1)^{3} - 3 \times 2 a \times 1 (2 a - 1)$
$= 8 a^{3} - 1 - 6 a (2 a - 1) = 8 a^{3} - 1 - 12 a^{2} + 6 a$
$= 8 a^{3} - 12 a^{2} + 6 a - 1$

Suggest Corrections

Similar questions

Find the cube of :

(i) $a + 2$

(ii) $2 a - 1$

(iii) $2 a + 3 b$

(iv) $3 b - 2 a$

(v) $2 x + \frac{1}{x}$

(vi) $x - \frac{1}{2}$

(2 a + \frac{1}{2 a}); a \neq 0

2 a + \frac{1}{2 a}

a \neq

(2 a - 3 b)

What is the cube of 2a?

Join BYJU'S Learning Program