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Question

Find the current flowing through the following electric circuit:
1026718_3b11c621d38a49399aebe0fa61c093a1.PNG

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Solution

Since, resistors 1Ω and 3Ω are in series,
Req1=1+3=4Ω
Now, resistors 4Ω and 6Ω are in parallel,
Req2=4Ω6Ω=4×64+6=2410=2.4Ω
Now, 3.6Ω,2.4Ω and 3Ω are again series,
Req=3.6+2.4+3=9Ω
Now, the current flowing the electric current I
I=VReq
I=4.99=0.5Amp
I=0.5Amp

953566_1026718_ans_07987a23fd2a483fbe59375376413b17.png

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