1
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Question

# Find the current I2.

A
104A
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B
2×104A
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C
3×104A
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D
5×104A
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Solution

## The correct option is A 10−4ALet’s find the total current given by the battery first. The resistors are in simple series-parallel combination where you can easily find out the equivalent resistance which comes out to be 12 Ohm. I guess you would have figured that out already. Applying the same old Ohm’s Law, V=IR We get, I=0.001 Amperes. This is the total current provided by the battery. The other 5 resistors in the circuit have been replaced with their equivalent counterpart. What we all need to find is I1 as per question. This is a trick question. As both resistors are of equal magnitude, total current gets equally distributed because as per Kirchhoff’s law no current can accumulate in between. Thus, I1=5×10−4 A. Hence D.

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