Question

Find the current through 25 V cell and power supplied by 20 V cell in the figure shown.

Answer 1

Applying KVL in loop ABCDA, ABFEA, ABGHA and ABJIA we get

$30-i_1\times 11=-25$ ...(i)

$20+i_2\times 5=25$ ...(ii)

$5-i_3\times 10=-25$ ...(iii)

$10+i_4\times 5=25$ ...(iv)

Solving equation (i), (ii), (iii) and (iv)

$i_1=5A,i_2=1A,i_3=3A$ and $i_4=3A$

Hence current flowing through $25v$ cell in

$i_1+i_2+i_3+i_4=5+1+3+3=12A$

Power supply by $20V$ is $i_{2}R=1\times 5=5w$