Find the difference between the mean and range of the following data set.
12, 86, 45, 78, 23, 56

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Solution

$M e a n = \frac{S u m o f a l l o b s e r v a t i o n s}{N u m b e r o f o b s e r v a t i o n s}$

$= \frac{12 + 86 + 45 + 78 + 23 + 56}{6}$

$= \frac{300}{6}$

= 50

Range = Highest observation - Lowest observation
= 86 - 12
= 74

Difference between the mean and range = 74 - 50 = 24

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