    Question

# Find the difference in oxidation numbers of sulphur in the (SO4)2− ion and SO3 compound.

A
2
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B
0.0
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C
-2
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D
1
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Solution

## The correct option is B 0Let the oxidation number of sulphur be x in (SO4)2− and y in SO3. Now the sulphate ion is given to us has a negative charge of -2 on it. This means that the sum of the oxidation numbers of all the elements in this ion is equal to -2 and not zero. The oxidation number of oxygen is -2. So let's calculate the value of x. x+4×(−2)=−2 x−8=−2 x=+6 Now let's calculate the oxidation number for sulphur in SO3. y + 3 times (-2) = 0 y - 6 = 0 y = +6 So the oxidation number of sulphur in (SO4)2− ion is +6. Hence the difference of oxidation number of sulphur in (SO4)2− and SO3 is +6 - (+6) = 0 The answer is 0.  Suggest Corrections  0      Similar questions  Related Videos   Oxidation number
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