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Question

Find the distance between the centre of gravity and centre of mass of a two-particle system attached to the ends of a light rod. Each particle has the same mass. Length of the rod is $$R$$, where $$R$$ is the radius of the earth.

42028_030fb193362844b19fff2f4d05ba1d41.png


A
R
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B
R2
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C
zero
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D
R4
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Solution

The correct option is B $$\dfrac{R}{2}$$
The centre of gravity of the Earth lie at its centre (Point p in picture)
The centre of mass of the rod is $$\cfrac { mR+m.0 }{ 2m } =\cfrac { R }{ 2 } \\ $$
The distance between CM of the rod and CG of the Earth is=$$\cfrac { R }{ 2 } $$ [$$PS=\cfrac { R }{ 2 } $$ in the picture] 

1128844_42028_ans_aa431faed9f647ca82b8c4f078c31942.png

Physics

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