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Question

Find the distance between the points P(2,4,1) and Q(1,2,5).

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Solution

We know, the distance between two points (x1,y1,z1) and (x2,y2,z2) is given as
Distance=(x2x1)2+(y2y1)2+(z2z1)2

PQ=(1(2))2+(24)2+(51)2=9+4+36=49=7 units

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