Question

Find the domain and range of the function $f\left(x\right)=\frac{1}{x-3}$

Answer 1

$f\left(x\right)=\frac{1}{x-3}$

$x-3\ne 0$

$x\ne 3$

So the Domain of $f\left(x\right)$ =$(-\infty ,\infty )-\left\{3\right\}$

The Range of $f\left(x\right)$ $-1\le f\left(x\right)\le 1$