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Question

Find the eccentricity of the hyperbola x2a2y2b2=1 which passes through the points (3,0) and
(32,2).

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Solution

The hyperbola x2a2y2b2=1 passes through the points (3,0) and (32,2).
So, a2=9 and b2=4
We know,
b2=a2(e21)

e2=139

e=133

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