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Byju's Answer
Standard XII
Mathematics
Properties of Orthogonality of Two Circles
Find the equa...
Question
Find the equation of a circle with centre
(
2
,
2
)
and passes through the point
(
4
,
5
)
.
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Solution
The centre of the circle is given as
(
h
,
k
)
=
(
2
,
2
)
.
Since, the circle passes through point
(
4
,
5
)
, the radius of the circle is distance between
(
2
,
2
)
and
(
4
,
5
)
.
r
=
√
(
2
−
4
)
2
+
(
2
−
5
)
2
=
√
4
+
9
=
√
13
Thus, the equation of the circle is :
(
x
−
2
)
2
+
(
y
−
2
)
2
=
13
x
2
−
4
x
+
4
+
y
2
−
4
y
+
4
=
13
x
2
+
y
2
−
4
x
−
4
y
−
5
=
0
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Properties of Orthogonality of Two Circles
Standard XII Mathematics
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