CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of a circle with centre (2,2) and passes through the point (4,5).

Open in App
Solution

The centre of the circle is given as (h,k)=(2,2).
Since, the circle passes through point (4,5), the radius of the circle is distance between (2,2) and (4,5).
r=(24)2+(25)2=4+9=13
Thus, the equation of the circle is :
(x2)2+(y2)2=13
x24x+4+y24y+4=13
x2+y24x4y5=0

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon