Find the equation of the chord of contacts of tangents drawn from a point $(2, 1)$ to the parabola $x^{2} = 2 y$

2 x = y - 1

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2 x = y + 1

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3 x = y + 1

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2 x = - y + 1

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Solution

The correct option is A $2 x = y + 1$
Required equation is given by, $T = 0$
$\Rightarrow x (2) - 2 \times \frac{1}{2} (y + 1) = 0$
$\Rightarrow 2 x = y + 1$

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Find the equation of the chord of contacts of tangents drawn from a point (2,1) to the parabola x2=2y

The correct option is A 2x=y+1Required equation is given by, T=0⇒x(2)−2×12(y+1)=0⇒2x=y+1

Find the equation of the chord of contacts of tangents drawn from a point $(2, 1)$ to the parabola $x^{2} = 2 y$

The correct option is A $2 x = y + 1$
Required equation is given by, $T = 0$
$\Rightarrow x (2) - 2 \times \frac{1}{2} (y + 1) = 0$
$\Rightarrow 2 x = y + 1$