Find the equation of the line joining the point $(2, - 9)$ and the point of intersection of lines $2 x + 5 y - 8 = 0$ and $3 x - 4 y - 35 = 0.$

x - y = 11

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x + y = 11

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y + x = 7

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x - y = 7

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Solution

The correct option is A $x - y = 11$
Intersection point of $2 x + 5 y - 8 = 0$ and $3 x - 4 y - 35 = 0$ is
$(9, - 2)$
Then equation of line passing through $(2, - 9)$ and $(9, - 2)$ is
$y + 9 = \frac{- 9 + 2}{2 - 9} (x - 2) \Rightarrow y + 9 = x - 2 \Rightarrow x - y = 11$

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and which dIvides the line segment joining the points

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Find the equation of the line joining the point (2,−9) and the point of intersection of lines 2x+5y−8=0 and 3x−4y−35=0.

The correct option is A x−y=11Intersection point of 2x+5y−8=0 and 3x−4y−35=0 is (9,−2)Then equation of line passing through (2,−9) and (9,−2) is y+9=−9+22−9(x−2)⇒y+9=x−2⇒x−y=11

Find the equation of the line joining the point $(2, - 9)$ and the point of intersection of lines $2 x + 5 y - 8 = 0$ and $3 x - 4 y - 35 = 0.$

The correct option is A $x - y = 11$
Intersection point of $2 x + 5 y - 8 = 0$ and $3 x - 4 y - 35 = 0$ is
$(9, - 2)$
Then equation of line passing through $(2, - 9)$ and $(9, - 2)$ is
$y + 9 = \frac{- 9 + 2}{2 - 9} (x - 2) \Rightarrow y + 9 = x - 2 \Rightarrow x - y = 11$