Question

Find the equation of the line parallel to the line $3x-4y+2=0$and passing through the point (-2, 3).

Answer 1

Slope of $3x-4y+2=0$ is $\frac{3}{4}$

So, equation of line parellal to $3x-4y+2$ and passing through $(-2,3)$ will be

$(y-3)=\frac{3}{4}(x+2)$

Thus equation will be

$4y-3x=18$

or $3x-4y+18=0$