Question

Find the equation of the line parallel to x-axis and passing through (3, -5).

Answer 1

$\text{Let the equation of the line be :}y-y_1=m(x-x_1)\text{Now,}m=0[\because \text{Parallel lines have equal slopes, the slope of x-axis is 0}](x_1,y_1)=(3,-5)\therefore y-y_1=m(x-x_1)y-(-5)=0(x-3)y+5=0y=-5\text{Hence, the equation of the required line is y = -5}$