Question

Find the equation of the line perpendicular to the line $2x+3y+5=0$ and passing through $(2,-3)$

Answer 1

We have the equation of line perpendicular to the line $2x+3y+5=0$ is $3x-2y=c$.......(1) where $c$ is constant.

According to the problem line (1) passes through the point $(2,-3)$ then we have $6+6=c$.

So the equation of the line is $3x-2y=12$.