Question

Find the equation of the line, whose :

(i) x-intercept = 5 and y-intercept = 3

(ii) x-intercept = -4 and y-intercept = 6

(iii) x-intercept = -8 and y-intercept = -4

Answer 1

(i) When x-intercept = 5, corresponding point on x-axis is (5, 0)

When y-intercept = 3, corresponding point on y-axis is (0, 3).

Let (x₁, y₁) = (5, 0) and (x₂, y₂) = (0, 3)

Slope =

The required equation is:

y - y₁ = m(x - x₁)

y - 0 = (x - 5)

5y = -3x + 15

3x + 5y = 15

(ii) When x-intercept = -4, corresponding point on x-axis is (-4, 0)

When y-intercept = 6, corresponding point on y-axis is (0, 6).

Let (x₁, y₁) = (-4, 0) and (x₂, y₂) = (0, 6)

Slope =

The required equation is:

y - y₁ = m(x - x₁)

y - 0 = (x + 4)

2y = 3x + 12

(iii) When x-intercept = -8, corresponding point on x-axis is (-8, 0)

When y-intercept = -4, corresponding point on y-axis is (0, -4).

Let (x₁, y₁) = (-8, 0) and (x₂, y₂) = (0, -4)

Slope =

The required equation is:

y - y₁ = m(x - x₁)

y - 0 = (x + 8)

2y = -x - 8

x + 2y + 8 = 0