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Question

Find the equation of the perpendicular bisector of the line segment joining the points (3, 4) and (1, 2).


A

2yx=5

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B

yx=5

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C

y+2x=5

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D

3y2x=5

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Solution

The correct option is C

y+2x=5


Midpoint of the points (3,4) and (1, 2)

=(312, 4+22)=(1, 3)

Slope of a line joining points (3, 4) and (1, 2) =2413=12

Slope of the required line = 2
[as they are perpendicular]

So, equation of required line is (y3)=(2)(x1)

y3=2x+2

2x+y=5.


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