CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of the plane passes through the point (1,3,2) and is perpendicular to planes x+2y+2z=5 and 3x+3y+2z=8.

Open in App
Solution

The equation of the plane passes through the point (1,3,2) is

a(x+1)+b(y3)+c(z2)=0 ........(1)

If this plane is perpendicular to the planes.

x+2y+2z=5

and 3x+3y+2z=8

then a+2b+2c=0 ..........(2)

and 3a+3b+2c=0 .........(3)

a46=b62=c36

a2=b+4=c3

a2=b4=c3=K

Let
a=2K,b=4K,c=3K

Putting the values of a,b,c in equation (1), we get the required equation of plane.

2K(x+1)4K(y3)+3K(z2)=0

2(x+1)4(y3)+3(z2)=0

2x+24y+12+3z6=0

2x4y+3z+8=0.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equation of a Plane: General Form and Point Normal Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon