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Question

Find the equation of the straight line passing through (3,2) and having slope 53

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Solution

Given:Slope=53

Point is (3,2)

Equation of the line is yy1=m(xx1)

y2=53(x+3)
3y6=5x15

3y6+5x+15=0

Equation of the line is 5x+3y+9=0

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