Question

Find the equivalent fraction of $\frac{3}{5}$, having:
(i) numerator $9$
(ii) denominator $30$
(iii) numerator $21$
(iv) denominator $40$

Answer 1

(i) $\frac{3}{5}=\frac{9}{}$

Consider the numerator.

As $3\times 3=9$,

we will multiply both the numerator & denominator by $3$.

$\frac{3\times 3}{5\times 3}=\frac{9}{\text{15}}$

(ii) $\frac{3}{5}=\frac{}{30}$

Consider the denominator.

As $5\times 6=30$,

we will multiply both the numerator & denominator by $6$.

$\frac{3\times 6}{5\times 6}$ = $\frac{\text{18}}{30}$

(iii) $\frac{3}{5}$=$\frac{21}{}$

Consider the numerator.

As $3\times 7=21,$

we will multiply both the numerator & denominator by $7.$

$\frac{3\times 7}{5\times 7}$=$\frac{21}{\text{35}}$

(iv) $\frac{3}{5}=\frac{}{40}$

Consider the denominator.

As $5\times 8=40,$

we will multiply both the numerator & denominator by $8$.

$\frac{3\times 8}{5\times 8}=\frac{\text{24}}{40}$