    Question

# Find the equivalent resistance between A & B in the circuit given below. A
18 Ω
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B
8.5 Ω
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C
16.5 Ω
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D
49 Ω
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Solution

## The correct option is C 16.5 ΩEquivalent resistance for series connection is: Req=R1+R2+R3+...+Rn Since 12 Ω & 18 Ω are in series, we can can calculate the equivalent resistance for this combination, R1eq=12+18=30Ω For parallel connection, equivalent resistance, 1Req=1R1+1R2+1R3+...+1Rn Now, R1eq & 10 Ω are in parallel Therefore, equivalent resistance for this combination is: ∴1R2eq=1R1eq+110=130+110=(1+330) ⇒1R2eq=430 ⇒R2eq=304=7.5 Ω Now, 9 Ω & R2eq are in series. ∴ Equivalent resistance for this combination is: R3eq=9+R2eq=9+7.5=16.5 Ω.  Suggest Corrections  0      Similar questions  Related Videos   Parallel Combination of Resistor_tackle
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