Question

Find the equivalent resistance between points A and B of the following network shown in the given diagram?

• A. $6\Omega$
• B. $8\Omega$
• C. $4\Omega$
• D. $10\Omega$

Answer 1

The correct option is B $8\Omega$

The three $3\Omega$ resistance in between are in parallel.
Can you see that?
n equal resistances R in a parallel combination will be equivalent to R/n . If you don’t get that try using
$\frac{1}{R_{eq}}=\frac{I}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$
So the middle combination becomes $\frac{3}{3}=1\Omega$
Then this $1\Omega$ will be in series with the other $1\Omega$ and $5\Omega$.
They will be added right?
Finally equivalent resistance becomes $7\Omega$.